0=24x^2+24x-4368

Solution for 0=24x^2+24x-4368 equation:

0=24x^2+24x-4368

We move all terms to the left:

0-(24x^2+24x-4368)=0

We add all the numbers together, and all the variables

-(24x^2+24x-4368)=0

We get rid of parentheses

-24x^2-24x+4368=0

a = -24; b = -24; c = +4368;
Δ = b2-4ac
Δ = -242-4·(-24)·4368
Δ = 419904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{419904}=648$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-648}{2*-24}=\frac{-624}{-48}
=+13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+648}{2*-24}=\frac{672}{-48}
=-14
$